Which two figures below have the same area? (Take π=227\pi = \frac{22}{7})

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Worked solution

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1. Calculate the area of Figure 1 (circle).

Radius of the circle =14÷2=7= 14 \div 2 = 7 cm.
Area of Figure 1 =πr2=227×72=154= \pi r^2 = \frac{22}{7} \times 7^2 = 154 cm2^2.

2. Calculate the area of Figure 2 (square).

Area of Figure 2 =12×12=144= 12 \times 12 = 144 cm2^2.

3. Calculate the area of Figure 3 (rectangle).

Area of Figure 3 =14×11=154= 14 \times 11 = 154 cm2^2.

4. Calculate the area of Figure 4 (triangle).

Area of Figure 4 =12×14×11=77= \frac{1}{2} \times 14 \times 11 = 77 cm2^2.

5. Compare the areas to find the two figures with the same area.

Figure 1 and Figure 3 both have an area of 154154 cm2^2.

Answer

Figure 1 and Figure 3 (option 2)

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