The figure below is made up of 2 identical quadrants of radius 7 cm that overlapped each other. The shaded square has sides of 3 cm. What is the area of the whole figure? (Take $\pi = \frac{22}{7}$)

1. Calculate the area of one quadrant.

Area of one quadrant = $\frac{1}{4} \times \pi \times r^2$
$= \frac{1}{4} \times \frac{22}{7} \times 7 \times 7$
$= \frac{1}{4} \times 154$
$= 38.5\text{ cm}^2$

2. Calculate the area of the overlapping square.

Area of square = $3 \times 3 = 9\text{ cm}^2$

3. Calculate the area of the whole figure.

Area of whole figure = Area of 2 quadrants - Area of overlapping square
$= 2 \times 38.5 - 9$
$= 77 - 9$
$= 68\text{ cm}^2$