Expand and simplify (3x−y)(y+x).(3x - y)(y + x). Factorise completely 3−12a23 - 12a^2.

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Worked solution

7(a)

1. Expand the product of the two brackets term by term.

(3x−y)(y+x)=3x(y+x)−y(y+x)(3x-y)(y+x)=3x(y+x)-y(y+x)

=3xy+3x2−y2−xy=3xy+3x^2-y^2-xy

2. Collect like terms and write the expression in simplified form.

3xy−xy=2xy3xy-xy=2xy

So,
(3x−y)(y+x)=3x2+2xy−y2.(3x-y)(y+x)=3x^2+2xy-y^2.

Answer

3x2+2xy−y23x^2+2xy-y^2

7(b)

1. Extract the common factor from both terms.

3−12a2=3(1−4a2)3-12a^2=3(1-4a^2)

2. Factorise the difference of two squares completely.

1−4a2=12−(2a)2=(1−2a)(1+2a)1-4a^2=1^2-(2a)^2=(1-2a)(1+2a)

So,
3−12a2=3(1−2a)(1+2a)3-12a^2=3(1-2a)(1+2a)

Answer

3(1−2a)(1+2a)3(1-2a)(1+2a)

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