A curve has equation y=x2+x+2k−4y = x^2 + x + 2k - 4 and a line has equation y−2x=ky - 2x = k, where kk is a constant. Find the set of values of kk for which the line and curve do not intersect and represent this set on a number line. Given that the curve with equation y=ax2+8x+cy = ax^2 + 8x + c, where aa and cc are constants, lies completely below the xx-axis.
Write down the conditions which must apply to aa and cc.
If xx is increasing at a rate of 0.20.2 units per second, find the rate of change of yy at the instant when y=−4y = -4.

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Worked solution

4(a)

1. Express $y$ in terms of $x$ from the linear equation and substitute into the curve equation

From the line equation, y=2x+ky = 2x + k.
Substitute into the curve equation:
2x+k=x2+x+2k−42x + k = x^2 + x + 2k - 4

2. Rearrange into a standard quadratic equation form $ax^2 + bx + c = 0$

x2+x−2x+2k−k−4=0x^2 + x - 2x + 2k - k - 4 = 0
x2−x+k−4=0x^2 - x + k - 4 = 0

3. Apply the discriminant condition for no intersection

For the line and curve to not intersect, the quadratic equation must have no real roots, so b2−4ac<0b^2 - 4ac < 0.
(−1)2−4(1)(k−4)<0(-1)^2 - 4(1)(k - 4) < 0

4. Solve the inequality for $k$

1−4k+16<01 - 4k + 16 < 0
17−4k<017 - 4k < 0
4k>174k > 17
k>4.25k > 4.25

5. Represent the solution on a number line

Draw a number line, place an open circle at 4.254.25 (or 174\frac{17}{4}), and draw an arrow pointing to the right to indicate values greater than 4.254.25.

Answer

k>4.25k > 4.25
(Represented on a number line with an open circle at 4.254.25 and an arrow pointing to the right)

4(b)

1. State the condition on the leading coefficient for the curve to lie completely below the $x$-axis

For the curve to lie completely below the xx-axis, it must open downwards. Therefore, the coefficient of x2x^2 must be negative:
a<0a < 0

2. Apply the discriminant condition for the curve not to intersect the $x$-axis

The curve must not intersect the xx-axis, so the equation ax2+8x+c=0ax^2 + 8x + c = 0 has no real roots. Thus, the discriminant must be less than zero:
b2−4ac<0b^2 - 4ac < 0
(8)2−4(a)(c)<0(8)^2 - 4(a)(c) < 0
64−4ac<064 - 4ac < 0
4ac>644ac > 64
ac>16ac > 16

Answer

a<0a < 0 and ac>16ac > 16

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