Charlotte the spider is walking along a web shaped like a 5-pointed star, shown in the figure below. The web has 5 outer points and 5 inner points. Each time Charlotte reaches a point, she randomly chooses a neighboring point and moves to that point. Charlotte starts at one of the outer points and makes 3 moves (revisiting points is allowed). What is the probability she is now at one of the inner points of the star ?
A. 14\frac{1}{4}
B. 25\frac{2}{5}
C. 12\frac{1}{2}
D. 35\frac{3}{5}
E. 34\frac{3}{4}

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Worked solution

1. 2026 AMC 8 官方解析

P外→内=1P_{\text{外} \to \text{内}} = 1 , P内→外=12P_{\text{内} \to \text{外}} = \frac{1}{2} , P内→内=12P_{\text{内} \to \text{内}} = \frac{1}{2}

外→1内{→12外→1内→12内→12内\text{外} \xrightarrow{\quad 1\quad } \text{内} \begin{cases} \xrightarrow{\frac{1}{2}} \text{外} \xrightarrow{\quad 1\quad } \text{内} \\ \xrightarrow{\frac{1}{2}} \text{内} \xrightarrow{\quad \frac{1}{2}\quad } \text{内} \end{cases}

P=1×12×1+1×12×12=34P = 1 \times \frac{1}{2} \times 1 + 1 \times \frac{1}{2} \times \frac{1}{2} = \frac{3}{4}

Answer

E. 34\frac{3}{4}

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