The diagram below shows the speed-time graph of a car's journey. For this journey, calculate

  1. ((a))

    the acceleration during the first 40 seconds,

    Answer ... m/s^2

  2. ((b))

    The total distance travelled.

    Answer ... m

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Worked solution

19((a))

1. Calculate the acceleration from the gradient of the speed-time graph during the first 40 seconds.

From t=0t=0 to t=40t=40, the speed increases from 00 m/s to 2424 m/s.

acceleration=change in speedtime taken=24−040=0.6\text{acceleration}=\frac{\text{change in speed}}{\text{time taken}}=\frac{24-0}{40}=0.6

Answer

0.6 m/s20.6\text{ m/s}^2

19((b))

1. Calculate the area under the speed-time graph.

Distance travelled == area under speed-time graph

Distance=12×60×24=720\text{Distance}=\frac{1}{2}\times 60\times 24=720

Answer

720 m720\text{ m}

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