一个长方形 PQRS 沿其对角线 PR 折叠，如下图所示。已知 $\angle\text{PRS} = 23^\circ$，求折叠后的 $\angle\text{QRS}$。 答：___ $^\circ$

1. Find the angle of the corner of the rectangle

In a rectangle, the corner angle is $90^\circ$. Therefore, $\angle\text{QRS} = 90^\circ$ before folding.

2. Determine the angle $\angle\text{PRQ}$ before folding

$\angle\text{PRQ} = 90^\circ - \angle\text{PRS} = 90^\circ - 23^\circ = 67^\circ$.

3. Use the property of folding to find the new position of $\angle\text{PRQ}$

When folded along PR, the triangle PQR is reflected. The new angle $\angle\text{PRQ}'$ (where Q' is the new position of Q) is equal to the original $\angle\text{PRQ}$, so $\angle\text{PRQ}' = 67^\circ$.

4. Calculate the new $\angle\text{QRS}$ after folding

The new $\angle\text{QRS}$ is the angle between the folded segment RQ' and the original segment RS. Since both are on the same side of PR after folding, the new $\angle\text{QRS} = \angle\text{PRQ}' - \angle\text{PRS} = 67^\circ - 23^\circ = 44^\circ$.