已知 cot⁡θ=−34\cot \theta = -\frac{3}{4} 且 tan⁡θ\tan \theta 与 cos⁡θ\cos \theta 异号,在不求出 θ\theta 的情况下,求下列各项的准确值。

  1. (a)

    cos⁡(−θ)\cos(-\theta),

  2. (b)

    sin⁡2θ\sin 2\theta

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完整解法

7(a)

1. Determine the quadrant of $\theta$ and find $\cos \theta$.

Since cot⁡θ=−34\cot \theta = -\frac{3}{4}, we have tan⁡θ=−43\tan \theta = -\frac{4}{3}.
As tan⁡θ\tan \theta is negative and tan⁡θ\tan \theta and cos⁡θ\cos \theta have opposite signs, cos⁡θ\cos \theta must be positive.
This means θ\theta lies in the 4th quadrant.
Using a right-angled triangle with opposite side 44 and adjacent side 33, the hypotenuse is 32+42=5\sqrt{3^2 + 4^2} = 5.
Therefore, cos⁡θ=35\cos \theta = \frac{3}{5}.

2. Evaluate $\cos(-\theta)$.

Using the property of the cosine function, cos⁡(−θ)=cos⁡θ\cos(-\theta) = \cos \theta.
cos⁡(−θ)=35\cos(-\theta) = \frac{3}{5}

答案

35\frac{3}{5}

7(b)

1. Determine the values of $\sin \theta$ and $\cos \theta$ based on the given conditions

Given cot⁡θ=−34\cot \theta = -\frac{3}{4}, we have tan⁡θ=−43\tan \theta = -\frac{4}{3}.
Since tan⁡θ\tan \theta is negative and cos⁡θ\cos \theta has the opposite sign, cos⁡θ\cos \theta must be positive. This places θ\theta in the 4th quadrant.
In the 4th quadrant, sin⁡θ\sin \theta is negative.
Using a right-angled triangle with opposite side 44 and adjacent side 33, the hypotenuse is 32+42=5\sqrt{3^2 + 4^2} = 5.
Thus, sin⁡θ=−45\sin \theta = -\frac{4}{5} and cos⁡θ=35\cos \theta = \frac{3}{5}.

2. Calculate $\sin 2\theta$ using the double angle formula

sin⁡2θ=2sin⁡θcos⁡θ\sin 2\theta = 2\sin \theta \cos \theta
sin⁡2θ=2(−45)(35)\sin 2\theta = 2\left(-\frac{4}{5}\right)\left(\frac{3}{5}\right)
sin⁡2θ=−2425\sin 2\theta = -\frac{24}{25}

答案

−2425-\frac{24}{25}

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