1. Substitute the partial fractions obtained in part (a)
From part (a), we have:
x2(2x−3)13x−6=−x3+x22+2x−36
∫x2(2x−3)13x−6dx=∫(−x3+2x−2+2x−36)dx
2. Integrate each term with respect to $x$
=−3lnx+−12x−1+26ln(2x−3)+c
=−3lnx−x2+3ln(2x−3)+c
答案−3lnx−x2+3ln(2x−3)+c