土壤的抗剪强度是指土壤抵抗张拉应力和承受荷载的能力。土壤的含水量是土壤质量中水的重量与固体重量之比。某土壤调查实验室从一处填海场地采集了土壤,以研究含水量对抗剪强度的影响。在不同含水量 (以百分比测量)下,收集到的抗剪强度 (以千帕(KPa)为单位)的信息呈现在下表中。
含水量, (%) 10.0 12.5 15.0 17.5 20.0 22.5 25.0 27.5 抗剪强度, (KPa) 2500 2100 1820 1630 1500 1410 1320 1270
| 含水量, (%) | 10.0 | 12.5 | 15.0 | 17.5 | 20.0 | 22.5 | 25.0 | 27.5 |
|---|---|---|---|---|---|---|---|---|
| 抗剪强度, (KPa) | 2500 | 2100 | 1820 | 1630 | 1500 | 1410 | 1320 | 1270 |
- (i)
绘制这些数据的散点图。利用你的图表解释 和 之间的关系是否能用形如 (其中 和 为常数)的方程进行良好的建模。
- (ii)
通过计算相关的样本相关系数,确定 和 之间的关系是用 还是 建模更好。解释你如何决定哪种模型更好,并给出该模型对应的方程。
- (iii)
使用你的方程来估算含水量为 40% 时的抗剪强度。解释你的估算是否可靠。
- (iv)
随后,已知信息表中未呈现一个数据点,且该数据点的加入并不影响 (ii) 中所得的适用方程。给出缺失数据点的抗剪强度,答案保留至最接近的整数。
- (v)
已知 1 兆帕 (MegaPascal) = 1000 千帕 (KiloPascal),重写你在 (ii) 中的方程,使其在抗剪强度以兆帕为单位时也能使用。解释相应的样本相关系数是否会与 (ii) 中计算出的系数有所不同。
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完整解法
9(i)
1. Draw the scatter diagram by plotting the given data points
Plot the points , , , , , , , on a set of axes with on the horizontal axis and on the vertical axis.
2. Explain whether the relationship is well modelled by a linear equation
Observe from the scatter diagram that as increases, decreases at a decreasing rate. The points exhibit a non-linear, curvilinear pattern rather than lying close to a straight line. Therefore, it is not likely to be well modelled by .
[Scatter diagram plotted with on the horizontal axis and on the vertical axis]
No, the relationship is not likely to be well modelled by an equation of the form because the points on the scatter diagram show a curve rather than a straight line.
9(ii)
1. Calculate the product moment correlation coefficient (PMCC) for the linear model $P = aw + b$.
Using a graphing calculator to find the PMCC for the data pairs :
2. Calculate the PMCC for the non-linear model $P = a\sqrt{w} + b$.
Using a graphing calculator to find the PMCC for the data pairs :
3. Determine and explain which is the better model by comparing the correlation coefficients.
Since (i.e. is closer to than ), there is a stronger linear correlation between and than between and .
Therefore, is the better model.
4. Find the values of $a$ and $b$ to state the equation for the chosen model.
From the graphing calculator, the linear regression of on gives the coefficients:
Rounding to 3 significant figures, we get and .
The equation is .
is the better model.
Equation:
9(iii)
1. Estimate the shear strength using the regression equation from (ii)
From (ii), the appropriate equation is (since its product moment correlation coefficient ), with and .
Substitute into the equation:
2. Explain the reliability of the estimate based on the data range
The value is outside the range of given water content data ().
This means the prediction requires extrapolation, so the estimate is not reliable.
The estimated shear strength is (to 3 s.f.). The estimate is unreliable because it involves extrapolation.
9(iv)
1. Identify that the missing data point corresponds to the sample mean of the given data.
A property of the least squares regression line is that it always passes through the sample mean point of the dataset, . Adding the mean point to the dataset will not change the means or the covariance, meaning the regression equation remains entirely unaffected. Since no specific independent variable value () is provided for the missing point, it must be the mean point, meaning its shear strength is .
2. Calculate the mean shear strength, $\bar{P}$.
Rounding to the nearest integer, the shear strength is KPa.
KPa
9(v)
1. State the original regression equation from (ii) and convert it to MegaPascal.
From (ii), comparing the PMCC of on () and on (), the better model is .
Calculating the regression coefficients gives the equation .
Let be the shear strength measured in MegaPascal. Since , we divide the values by 1000:
2. Explain the effect of the unit conversion on the product moment correlation coefficient.
The product moment correlation coefficient (PMCC) would not differ.
Converting the units by dividing the shear strength by 1000 is a linear transformation (scaling by a positive constant). The PMCC is invariant under linear transformations with a positive scale factor because it purely measures the strength of the linear correlation between the two variables, completely independent of the units used.
The product moment correlation coefficient would not differ, as changing units is a linear transformation which does not affect the strength of the linear correlation.
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