A curve whose equation is y=1x+1y = \dfrac{1}{x+1}, undergoes in succession the following transformations: A: A reflection in the x-axis, B: A translation of magnitude 1 unit in the y-direction, C: A scaling parallel to the y-axis by a factor 2. Give the equation of the resulting curve. A curve undergoes in succession the transformations A, B and C as above and the equation of the resulting curve is y=2−∣2x+6∣y = 2 - |2x+6|. Determine the equation of the curve before the transformations were effected.

Work through it with AI →

It won't just hand you the answer — it asks where you're stuck.How the checker works

Worked solution

4

1. Apply the sequence of transformations to the curve $y = \frac{1}{x+1}$.

Applying Transformation A (reflection in the xx-axis):
y=−1x+1y = -\frac{1}{x+1}

Applying Transformation B (translation of magnitude 1 unit in the yy-direction):
y=−1x+1+1=1−1x+1y = -\frac{1}{x+1} + 1 = 1 - \frac{1}{x+1}

Applying Transformation C (scaling parallel to the yy-axis by a factor of 2):
y=2(1−1x+1)=2−2x+1y = 2\left(1 - \frac{1}{x+1}\right) = 2 - \frac{2}{x+1}

2. Find the combined transformation for a general curve $y = \mathrm{f}(x)$.

For a general curve y=f(x)y = \mathrm{f}(x), undergoing the same succession of transformations:
After A: y=−f(x)y = -\mathrm{f}(x)
After B: y=−f(x)+1y = -\mathrm{f}(x) + 1
After C: y=2(−f(x)+1)=2−2f(x)y = 2(-\mathrm{f}(x) + 1) = 2 - 2\mathrm{f}(x)

3. Equate the transformed general function to the given resulting curve and solve for the original curve equation.

We are given that the resulting curve is y=2−∣2x+6∣y = 2 - |2x+6|. Equating this to the combined transformation:
2−2f(x)=2−∣2x+6∣2 - 2\mathrm{f}(x) = 2 - |2x+6|
−2f(x)=−∣2x+6∣-2\mathrm{f}(x) = -|2x+6|
2f(x)=∣2x+6∣2\mathrm{f}(x) = |2x+6|

Solving for f(x)\mathrm{f}(x) and simplifying the modulus expression:
f(x)=12∣2(x+3)∣\mathrm{f}(x) = \frac{1}{2}|2(x+3)|
f(x)=∣x+3∣\mathrm{f}(x) = |x+3|

The equation of the original curve is y=∣x+3∣y = |x+3|.

Answer

Resulting curve: y=2−2x+1y = 2 - \frac{2}{x+1}
Original curve: y=∣x+3∣y = |x+3|

AI analysis — may contain mistakes.

Worked this one out on paper? Snap your steps and Gigle's AI math checker will circle the step where it went wrong.

More questions on this topic

  1. 1将函数f(x)=sin⁡2xf(x)=\sin 2x的图象保持纵坐标不变,先将横坐标缩短为原来的12\dfrac{1}{2},再向右平移π6\dfrac{π}{6}个单位长度后得到g(x)g(x),则g(x)g(x)的解析式为()(\quad)…
  2. 2By expressing the equation of the curve y=12x+112x+1y = \frac{12x + 11}{2x + 1} in the form y=A+B2x+1y = A + \frac{B}{2x + 1}, where AA…
  3. 3A curve C1C_1 has the equation p2x2−y2=p2p^2x^2 - y^2 = p^2 where p>1p > 1. Sketch C1C_1, stating the coordinates of any points o…
  4. 4The diagram shows the graphs of y=f(∣x∣)y = \mathrm{f}(|x|) and y=f′(x)y = \mathrm{f}'(x). The graph of y=f(∣x∣)y = \mathrm{f}(|x|) has t…
  5. 5The curve C1C_1 with equation x2a2+y24a2=1\frac{x^2}{a^2}+\frac{y^2}{4a^2}=1 is transformed to curve C2C_2 by a translation of aa…