The cost of 3 chairs and 5 tables is $360. The cost of 6 chairs and 15 tables is $900. What is the cost of 1 table? (Round off the answer to the nearest $10.) Answer: $ ___

1. Set up equations for the given scenarios

Let $c$ be the cost of 1 chair and $t$ be the cost of 1 table.
$3c + 5t = 360$ --- (1)
$6c + 15t = 900$ --- (2)

2. Eliminate $c$ to find $t$

Multiply equation (1) by 2:
$6c + 10t = 720$ --- (3)

Subtract equation (3) from equation (2):
$(6c + 15t) - (6c + 10t) = 900 - 720$
$5t = 180$
$t = 36$

3. Round off the answer to the nearest $10

$36 \approx 40$ (to the nearest 10)