Two years ago, Andy was nn years older than Belle. Andy is twice her age now, how old was Belle 2 years ago?

Work through it with AI →

It won't just hand you the answer — it asks where you're stuck.How the checker works

Worked solution

11

1. Identify the constant difference in their ages.

The difference in age between two people remains constant over time. Since Andy was nn years older than Belle two years ago, Andy is still nn years older than Belle now.

2. Formulate an equation for their current ages and solve for Belle's current age.

Let Belle's current age be BB.
Andy's current age is B+nB + n.
We are given that Andy is twice Belle's age now:
B+n=2BB + n = 2B
B=nB = n

3. Find Belle's age 2 years ago.

Belle's age 2 years ago was:
B−2=n−2B - 2 = n - 2

Answer

n−2n - 2 (option 3)

AI analysis — may contain mistakes.

Worked this one out on paper? Snap your steps and Gigle's AI math checker will circle the step where it went wrong.

More questions on this topic

  1. 1Containers X and Y are rectangular containers. The base area of Container X is 30 cm^2 and the base area of Container Y…
  2. 2Andy had $5x. After buying apples at 60c each, he had $2x left. How many apples did Andy buy? Answer: ___
  3. 3n is a positive integer. Explain whether, for all n, (7n+2)2−(7n−1)2(7n+2)^{2}-(7n-1)^{2} is a multiple of 3. Answer ___
  4. 4A bag contains 4 black coins, 7 red coins and 11 white coins. Two coins are drawn from the bag at random, one after anot…
  5. 5给出下列判断:①单项式−12px2-\dfrac{1}{2}px^{2}的系数为−12-\dfrac{1}{2};②整式x−2xy+1x-2xy+1是二次三项式;③多项式3x2y3−px5+12y3x^{2}y^{3}-px^{5}+\dfrac{1}{2}y的次数…