The diagram shows the positions of points A, B and C. $\angle ABC = 60^\circ$, $\angle BCA = 54^\circ$ and the bearing of B from A is $078^\circ$. Find the bearing of

1. Find the angle between $AB$ and $AC$ at A, then determine the bearing of C from A.

$\angle BAC=180^\circ-60^\circ-54^\circ=66^\circ$

Since the bearing of B from A is $078^\circ$ and $AC$ is $66^\circ$ to the left of $AB$,
$\text{bearing of C from A}=078^\circ-66^\circ=012^\circ.$

1. Find the bearing of C from B using the reverse bearing of B from A and the angle at B.

Bearing of A from B:
$078^\circ+180^\circ=258^\circ$
Since $\angle ABC=60^\circ$, the bearing of C from B is
$258^\circ-60^\circ=198^\circ.$

2. Find the bearing of B from C as the reverse of the bearing of C from B.

Bearing of B from C:
$198^\circ-180^\circ=018^\circ.$