Calculate $\displaystyle \frac{\sqrt[3]{123^2}}{\dfrac{3}{5.01}+2}$. Answer ... An item costs $24 when rounded off to the nearest dollar.
What is the maximum possible price of the item? Answer $...

1. Calculate the value of the numerical expression

$\frac{\sqrt[3]{123^2}}{\dfrac{3}{5.01}+2}=9.516\ldots$

To 3 significant figures,
$9.516\ldots \approx 9.52$

1. Find the greatest price that would round to \$24 to the nearest dollar

A price that rounds to $24 to the nearest dollar satisfies

$\$23.50 \leq \text{price} < \$24.50.$

Since money is stated to the nearest cent, the maximum possible price is

$\$24.49.$