The figure below is made up of four squares of sides 10 cm, four quadrants and eight semicircles. Find the total area of the shaded parts. (Take π=3.14\pi = 3.14) Answer: ___

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Worked solution

1. 计算单个边长为 $10\text{ cm}$ 的正方形中扇形与两个半圆的面积

在一个边长为 10 cm10\text{ cm} 的正方形中:
半径为 10 cm10\text{ cm} 的扇形(扇形/四分之一圆)面积为:
扇形面积=14×π×102=25π=25×3.14=78.5 cm2\text{扇形面积} = \frac{1}{4} \times \pi \times 10^2 = 25\pi = 25 \times 3.14 = 78.5\text{ cm}^2
以正方形两条邻边为直径的两个半圆(半径为 5 cm5\text{ cm})的总面积为:
两个半圆总面积=2×(12×π×52)=25π=78.5 cm2\text{两个半圆总面积} = 2 \times \left(\frac{1}{2} \times \pi \times 5^2\right) = 25\pi = 78.5\text{ cm}^2

2. 计算两个半圆重叠部分(叶形/花瓣)的面积

两个半圆在边长为 5 cm5\text{ cm} 的角落小正方形内重叠,形成一个由两个半径为 5 cm5\text{ cm} 的四分之一圆重叠而成的叶形:
叶形面积=2×(14×3.14×52)−(5×5)=39.25−25=14.25 cm2\text{叶形面积} = 2 \times \left(\frac{1}{4} \times 3.14 \times 5^2\right) - (5 \times 5) = 39.25 - 25 = 14.25\text{ cm}^2

3. 利用容斥原理与等积变换求出单个正方形内阴影部分的面积

在单个正方形中,位于扇形内部但位于两个半圆外部的阴影面积为:
单个正方形阴影面积=扇形面积−两个半圆总面积+叶形面积\text{单个正方形阴影面积} = \text{扇形面积} - \text{两个半圆总面积} + \text{叶形面积}
单个正方形阴影面积=78.5−78.5+14.25=14.25 cm2\text{单个正方形阴影面积} = 78.5 - 78.5 + 14.25 = 14.25\text{ cm}^2

4. 计算 4 个正方形中阴影部分的总面积

图理由 4 个相同的正方形组成,因此阴影部分的总面积为:
阴影总面积=4×14.25=57 cm2\text{阴影总面积} = 4 \times 14.25 = 57\text{ cm}^2

Answer

57 cm257\text{ cm}^2

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