Raju, Sam and Tristan had a total of $435. Raju spent 45\frac{4}{5} of his money, Sam spent 23\frac{2}{3} and Tristan spent 34\frac{3}{4} of his money. In the end, Raju had $55 more than Sam and Tristan had $10 more than Sam. How much money did Tristan have at first? Ans : ___

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Worked solution

15

1. Express the remaining money of each person in terms of units

Let Sam's remaining money be 11 unit (1u1u).
Since Raju had $55\char36{}55 more than Sam in the end, Raju's remaining money is 1u+551u + 55.
Since Tristan had $10\char36{}10 more than Sam in the end, Tristan's remaining money is 1u+101u + 10.

2. Relate the remaining money to the total money at first using fractions

Raju spent 45\frac{4}{5}, so he had 15\frac{1}{5} left. His total money at first was 5×(1u+55)=5u+2755 \times (1u + 55) = 5u + 275.
Sam spent 23\frac{2}{3}, so he had 13\frac{1}{3} left. His total money at first was 3×1u=3u3 \times 1u = 3u.
Tristan spent 34\frac{3}{4}, so he had 14\frac{1}{4} left. His total money at first was 4×(1u+10)=4u+404 \times (1u + 10) = 4u + 40.

3. Form an equation for the total money at first and solve for 1 unit

Total money at first = (5u+275)+3u+(4u+40)=12u+315(5u + 275) + 3u + (4u + 40) = 12u + 315.
We are given the total is $435\char36{}435.
12u+315=43512u + 315 = 435
12u=435−315=12012u = 435 - 315 = 120
1u=101u = 10

4. Calculate Tristan's money at first

Tristan's money at first = 4u+404u + 40
=4(10)+40= 4(10) + 40
=40+40=80= 40 + 40 = 80

Answer

$120

AI analysis — may contain mistakes.

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