The quadratic curve y=x2+4x−21y = x^2 + 4x - 21 can be written as y=(x−a)(x+b).y = (x - a)(x + b).

  1. (a)

    Find the value of a and the value of b, where a and b are positive integers.

    Answer a = ___

    b = ___

  2. (b)

    Explain why yy will not have a value smaller than −25-25.

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Worked solution

6(a)

1. Find the two required factors of the quadratic expression.

For x2+4x−21x^2+4x-21, find two numbers with product −21-21 and sum 44.

The numbers are −3-3 and 77, since
(−3)(7)=−21and−3+7=4.(-3)(7)=-21 \quad \text{and} \quad -3+7=4.

2. Write the quadratic in factorised form and compare with the given form.

So
x2+4x−21=(x−3)(x+7).x^2+4x-21=(x-3)(x+7).

Comparing with
(x−a)(x+b),(x-a)(x+b),
we get
a=3,b=7.a=3,\quad b=7.

Answer

a=3a=3

b=7b=7

6(b)

1. Rewrite the quadratic in completed-square form and use the fact that a square is non-negative.

y=x2+4x−21y=x^2+4x-21
y=(x+2)2−25y=(x+2)^2-25
Since (x+2)2⩾0(x+2)^2 \geqslant 0 for all real values of xx,
y=(x+2)2−25⩾−25.y=(x+2)^2-25 \geqslant -25.
Therefore, yy will not have a value smaller than −25-25.

Answer

y=(x+2)2−25y=(x+2)^2-25. Since (x+2)2⩾0(x+2)^2 \geqslant 0, y⩾−25y \geqslant -25. Hence yy will not have a value smaller than −25-25.

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