Write down the first 3 terms in the expansion of $\left(2 - \frac{x}{3}\right)^6$, in ascending power of $x$.
All terms must be expressed in the simplest form. Hence, find the term independent of $x$ in the expansion of $\left(2 - \frac{x}{3}\right)^6 \left(\frac{4}{x} - x\right)^2$.

1. Apply the binomial theorem to expand the first three terms

$\left(2 - \frac{x}{3}\right)^6 = 2^6 + \binom{6}{1}2^5\left(-\frac{x}{3}\right) + \binom{6}{2}2^4\left(-\frac{x}{3}\right)^2 + \dots$

2. Evaluate the coefficients and simplify the terms

$= 64 + 6(32)\left(-\frac{x}{3}\right) + 15(16)\left(\frac{x^2}{9}\right) + \dots$
$= 64 - 64x + \frac{240}{9}x^2 + \dots$

3. State the final simplified expression for the first three terms

$= 64 - 64x + \frac{80}{3}x^2$