Figera has two 10% coins, six 20% coins and three 50% coins. What is the least number of coins that she can use to make $2?

1. Convert the target amount to cents and determine the strategy to minimize the number of coins.

Target amount = $\char36{}2 = 200$ cents.
To use the least number of coins, we must use as many of the largest denomination coins as possible.

2. Use the maximum possible number of 50-cent coins.

We have three $50$-cent coins.
Value = $3 \times 50 = 150$ cents.
Number of coins used = $3$.
Remaining amount = $200 - 150 = 50$ cents.

3. Use the next largest denomination (20-cent coins) for the remaining amount.

We need to make $50$ cents using $20$-cent and $10$-cent coins.
Maximum number of $20$-cent coins we can use without exceeding $50$ cents is $2$.
Value = $2 \times 20 = 40$ cents.
Number of coins used = $2$.
Remaining amount = $50 - 40 = 10$ cents.

4. Use the 10-cent coins for the final remaining amount and find the total number of coins.

We need $10$ cents, which requires one $10$-cent coin.
Number of coins used = $1$.
Total number of coins = $3 + 2 + 1 = 6$.