The R0R_{0} value of a virus refers to the average number of new infections resulting from each infected person. (a) A new virus is discovered. Extensive testing reveals that by the nthn^{\text{th}} day, a total of 268 people were infected. In the following day, 686 people were newly infected. In the day following that, 2401 people were newly infected. Virologists propose to use a geometric progression to model the number of infections due to the virus. They propose the model: un=aR0 n−1u_{n}=aR_{0}^{\,n-1} where unu_{n} is the number of new infections on the nthn^{\text{th}} day after the virus emerged, and aa is the number of people infected initially.

  1. (a(i))

    Using this model, estimate the value of R0R_{0}.

Work through it with AI →

It won't just hand you the answer — it asks where you're stuck.How the checker works

Worked solution

8(a(i))

1. Identify consecutive terms of the geometric progression from the given context.

From the problem, the number of new infections on consecutive days (after the nthn^{\text{th}} day) represent consecutive terms in the geometric progression model. Let these be the (n+1)th(n+1)^{\text{th}} and (n+2)th(n+2)^{\text{th}} days:
un+1=686u_{n+1} = 686
un+2=2401u_{n+2} = 2401

2. Calculate the common ratio $R_0$ by dividing the consecutive terms.

Since the model is a geometric progression with common ratio R0R_0:
R0=un+2un+1R_0 = \frac{u_{n+2}}{u_{n+1}}
R0=2401686R_0 = \frac{2401}{686}
R0=3.5R_0 = 3.5

Answer

3.53.5

AI analysis — may contain mistakes.

Worked this one out on paper? Snap your steps and Gigle's AI math checker will circle the step where it went wrong.

More questions on this topic

  1. 1The sum of the first nn terms of a series is given by Sn=3n(n+2)S_n = 3n(n + 2). Show that this series follows an arithmetic pr…
  2. 2The sum of the first nn terms of a series is given by Sn=3n(n+2)S_n = 3n(n + 2). Show that this series follows an arithmetic pr…
  3. 3等比数列{an}\{a_{n}\}中,若a2a_{2}、a4a_{4}是方程2x2−11x+8=02x^{2}-11x+8=0的两根,则a3a_{3}的值为()(\quad) A. 22 B. ±2±2 C. 2\sqrt{2}…
  4. 4The sum of the first 100 terms of an arithmetic progression is 10,000. The first, second and fifth terms of this progres…
  5. 5A sequence of numbers u1,u2,u3,…u_{1}, u_{2}, u_{3}, \ldots has sum SnS_{n} where Sn=∑r=1nurS_{n} = \sum_{r=1}^{n} u_{r}. It is given th…