The diagram below shows a triangle ABC.

  1. (a)

    Construct the perpendicular bisector of AC.

  2. (b)

    Construct the bisector of angle BCA.

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Worked solution

13(a)

1. Construct equal arcs from $A$ and $C$ and draw the bisector line.

Set the compass to a radius greater than half of ACAC. With centre AA, draw arcs above and below ACAC. Using the same radius and centre CC, draw arcs to intersect the first pair of arcs. Join the two intersection points with a straight line. This line is the perpendicular bisector of ACAC.

Answer

The perpendicular bisector of ACAC is constructed.

13(b)

1. Construct the angle bisector of $\angle BCA$ using arcs.

With centre CC, draw an arc cutting CBCB and CACA at two points. Using these two points as centres and the same radius, draw two arcs that intersect inside ∠BCA\angle BCA. Draw a straight line from CC to this intersection point. This line is the bisector of ∠BCA\angle BCA.

Answer

The bisector of angle BCABCA is constructed.

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