The diagram shows a line segment PQ.

- (i)
Construct the perpendicular bisector of PQ, showing your constructions clearly.
Answer
- (ii)
Explain clearly why your construction method gives the perpendicular bisector of PQ.
Answer
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Worked solution
12(i)
1. Draw equal-radius arcs from both endpoints and join their intersections
Set the compass radius to more than half of .
With centre , draw arcs above and below .
Using the same radius and centre , draw arcs to intersect the first pair of arcs at two points.
Draw a straight line through the two intersection points. This line is the perpendicular bisector of .
The perpendicular bisector of is the straight line drawn through the two intersection points of the equal-radius arcs above and below .
12(ii)
1. State why each arc intersection point is equidistant from $P$ and $Q$
Let the two intersection points of the arcs be and .
Since the arcs drawn with centres and have the same radius,
and .
2. Apply the perpendicular bisector property to justify the constructed line
A point equidistant from and lies on the perpendicular bisector of .
Since both and are equidistant from and , the line through and is the perpendicular bisector of .
Let the two arc intersection points be and . Since the arcs drawn from and have the same radius, and . Hence and are both equidistant from and , so they lie on the perpendicular bisector of . Therefore the line is the perpendicular bisector of .
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