The Ideal Gas Law $PV = 8.3145\,nT$ relates pressure P (measured in Pascal), volume V (measured in metres^3), the number of moles of a gas n (measured in moles), and temperature T (measured in Kelvins). One mole of gas is found to exert a pressure of 101 325 Pascal at room temperature 293 Kelvins. Find the volume of the gas in cm^3. Answer ...cm^3

1. Substitute the given values and solve for $V$ in cubic metres

Given $P=101325$, $n=1$ and $T=293$,

$PV=8.3145nT$

$101325V=8.3145(1)(293)$

$V=\frac{8.3145\times293}{101325}$

$V\approx0.0240429\text{ m}^3$

2. Convert the volume from cubic metres to cubic centimetres

Since $1\text{ m}=100\text{ cm}$,

$1\text{ m}^3=100^3\text{ cm}^3=1000000\text{ cm}^3$

$0.0240429\text{ m}^3\times1000000\approx24043\text{ cm}^3$