The diagram shows a quadrilateral WXYZ.

- (a)
Construct the perpendicular bisector of XY.
- (b)
Construct the bisector of angle WXY.
- (c)
Point A in the quadrilateral is equidistant from X and Y and is closer to the line WX then to line XY.
Mark and label a possible location for point A in the diagram above.
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Worked solution
13(a)
1. Construct equal-radius arcs from the endpoints of $XY$ and draw the bisector line.
Set the compass radius to more than half of .
With centre , draw arcs above and below . Using the same radius and centre , draw arcs above and below to intersect the first pair of arcs.
Join the two arc-intersection points with a straight line. This line is the perpendicular bisector of .
The perpendicular bisector of is drawn: a straight line through the two equal-radius arc intersections, crossing at right angles and bisecting .
13(b)
1. Construct the angle bisector of $angle WXY$.
With centre , draw an arc cutting and at two points. Using the same radius from these two points, draw two arcs meeting inside angle WXY. Draw a straight line from through the intersection of the arcs. This line is the bisector of angle WXY.
The bisector of angle WXY is drawn: a straight line from through the intersection of the two equal-radius arcs inside the angle.
13(c)
1. Identify the required region and mark a valid point $A$.
Since is equidistant from and , must lie on the perpendicular bisector of .
Since is closer to line than to line , choose the point on the side of the angle bisector of nearer to , not the side nearer to .
Therefore, mark and label any point inside the quadrilateral on the perpendicular bisector of and on the side of the angle bisector.
Mark at any point inside quadrilateral on the perpendicular bisector of , on the side of the angle bisector of nearer to line .
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