The diagram shows a quadrilateral WXYZ.

  1. (a)

    Construct the perpendicular bisector of XY.

  2. (b)

    Construct the bisector of angle WXY.

  3. (c)

    Point A in the quadrilateral is equidistant from X and Y and is closer to the line WX then to line XY.
    Mark and label a possible location for point A in the diagram above.

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Worked solution

13(a)

1. Construct equal-radius arcs from the endpoints of $XY$ and draw the bisector line.

Set the compass radius to more than half of XYXY.

With centre XX, draw arcs above and below XYXY. Using the same radius and centre YY, draw arcs above and below XYXY to intersect the first pair of arcs.

Join the two arc-intersection points with a straight line. This line is the perpendicular bisector of XYXY.

Answer

The perpendicular bisector of XYXY is drawn: a straight line through the two equal-radius arc intersections, crossing XYXY at right angles and bisecting XYXY.

13(b)

1. Construct the angle bisector of $angle WXY$.

With centre XX, draw an arc cutting XWXW and XYXY at two points. Using the same radius from these two points, draw two arcs meeting inside angle WXY. Draw a straight line from XX through the intersection of the arcs. This line is the bisector of angle WXY.

Answer

The bisector of angle WXY is drawn: a straight line from XX through the intersection of the two equal-radius arcs inside the angle.

13(c)

1. Identify the required region and mark a valid point $A$.

Since AA is equidistant from XX and YY, AA must lie on the perpendicular bisector of XYXY.

Since AA is closer to line WXWX than to line XYXY, choose the point on the side of the angle bisector of ∠WXY\angle WXY nearer to WXWX, not the side nearer to XYXY.

Therefore, mark and label any point AA inside the quadrilateral on the perpendicular bisector of XYXY and on the WXWX side of the angle bisector.

Answer

Mark AA at any point inside quadrilateral WXYZWXYZ on the perpendicular bisector of XYXY, on the side of the angle bisector of ∠WXY\angle WXY nearer to line WXWX.

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