13 pots of plants are arranged in a row of equal distance apart. The distance between the first pot of plant and the fifth pot of plant is $1\frac{3}{4}$ m. What is the distance between the $2^{\text{nd}}$ pot of plant and the $12^{\text{th}}$ pot of plant?

1. Find the number of intervals between the 1st and 5th pot

Number of intervals between 1st and 5th pot $= 5 - 1 = 4$

2. Calculate the distance of one interval

Distance of 4 intervals $= 1\frac{3}{4} = \frac{7}{4}$ m
Distance of 1 interval $= \frac{7}{4} \div 4 = \frac{7}{16}$ m

3. Find the number of intervals between the 2nd and 12th pot

Number of intervals between 2nd and 12th pot $= 12 - 2 = 10$

4. Calculate the distance between the 2nd and 12th pot

Distance $= 10 \times \frac{7}{16} = \frac{70}{16} = \frac{35}{8} = 4\frac{3}{8}$ m