The mass of Jupiter is approximately 1.90×10^27 kg. The mass of Earth is approximately 5.97×10^24 kg.

1. Find the ratio of Jupiter's mass to Earth's mass and express it in standard form.

$\frac{1.90\times10^{27}}{5.97\times10^{24}}=\frac{1.90}{5.97}\times10^{27-24}$
$=0.318257\ldots\times10^3=3.18257\ldots\times10^2$
$\approx 3.18\times10^2$

1. Calculate Jupiter's density using mass divided by volume.

$\text{Density of Jupiter}=\frac{1.90\times 10^{27}}{1.43\times 10^{24}}$
$=1.328\ldots\times 10^3$
$\approx 1.33\times 10^3\text{ kg/m}^3$

2. Calculate Earth's density and compare it with Jupiter's density.

$\text{Density of Earth}=\frac{5.97\times 10^{24}}{1.08\times 10^{21}}$
$=5.527\ldots\times 10^3$
$\approx 5.53\times 10^3\text{ kg/m}^3$
Since $5.53\times 10^3>1.33\times 10^3$, Earth has the higher density.