The first 15 numbers of a number pattern are given below. 9,0,8,6,9,0,8,6,9,0,8,6,9,0,8,…9, 0, 8, 6, 9, 0, 8, 6, 9, 0, 8, 6, 9, 0, 8, \dots
1st15th\text{1}^{\text{st}} \hspace{6.5cm} \text{15}^{\text{th}}
What is the 274th274^{\text{th}} number?

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Worked solution

15

1. Identify the repeating sequence and its length.

The pattern is 9,0,8,69, 0, 8, 6, which repeats every 44 numbers.

2. Divide the target position by the length of the repeating sequence to find the remainder.

274÷4=68274 \div 4 = 68 with a remainder of 22.

3. Determine the number at the target position based on the remainder.

A remainder of 22 means the 274th274^{\text{th}} number is the 2nd2^{\text{nd}} number in the repeating sequence, which is 00.

Answer

00 (option 1)

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