A car and a bike set off from Town B in opposite directions at 09 30. The car travelled towards Town A at a constant speed of 80 km/h while the bike travelled towards Town C at a constant speed of 62 km/h. When the car reached Town A at 12 30, the bike was still 28 km away from Town C.

1. Calculate the time taken by the car to travel from Town B to Town A

Time taken = $12\ 30 - 09\ 30 = 3$ hours

2. Calculate the distance travelled by the car

Distance = Speed $\times$ Time = $80 \times 3 = 240$ km

1. Calculate the distance the bike travelled in 3 hours

Time taken from 09 30 to 12 30 is $3$ hours.
Distance travelled by bike $= 62 \times 3 = 186$ km

2. Calculate the total distance between Town A and Town C

Distance from Town A to Town B $= 80 \times 3 = 240$ km (from part a)
Distance from Town B to Town C $= 186 + 28 = 214$ km
Total distance between Town A and Town C $= 240 + 214 = 454$ km