Factorise a4−b2a^4 - b^2. Answer ... Factorise completely 8xy−1−4x+2y8xy - 1 - 4x + 2y. Answer ...

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Worked solution

12(a)

1. Apply the difference of squares identity

a4−b2=(a2)2−b2a^4-b^2=(a^2)^2-b^2

Using x2−y2=(x+y)(x−y)x^2-y^2=(x+y)(x-y),

a4−b2=(a2+b)(a2−b)a^4-b^2=(a^2+b)(a^2-b)

Answer

(a2+b)(a2−b)(a^2+b)(a^2-b)

12(b)

1. Group terms to obtain a common binomial factor

8xy−1−4x+2y8xy - 1 - 4x + 2y

=8xy−4x+2y−1= 8xy - 4x + 2y - 1

=4x(2y−1)+1(2y−1)= 4x(2y-1) + 1(2y-1)

2. Factorise the common binomial factor completely

4x(2y−1)+1(2y−1)4x(2y-1) + 1(2y-1)

=(2y−1)(4x+1)= (2y-1)(4x+1)

Answer

(2y−1)(4x+1)(2y-1)(4x+1)

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