A new housing estate is represented by an area of 200 cm^2 on a Map A drawn to a scale of 1 : n. Given that the actual area of the estate is 32 km^2, find the value of n. Answer n = ___ The scale of another map, Map B is 1 : 65 000.
The length of a road on Map B is 50 cm.
Find the length of the road on Map A.
Answer ___ cm

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Worked solution

10(a)

1. Convert the actual area from km² to cm².

Since 1 km=100000 cm1\text{ km}=100000\text{ cm},

1 km2=(100000)2 cm2=1010 cm21\text{ km}^2=(100000)^2\text{ cm}^2=10^{10}\text{ cm}^2

32 km2=32×1010=320000000000 cm232\text{ km}^2=32\times 10^{10}=320000000000\text{ cm}^2

2. Use the area scale to find the linear scale denominator $n$.

Map area : actual area

200:320000000000=1:1600000000200:320000000000=1:1600000000

For a scale of 1:n1:n, the area ratio is

12:n2=1:n21^2:n^2=1:n^2

So

n2=1600000000n^2=1600000000

n=1600000000=40000n=\sqrt{1600000000}=40000

Answer

n=40000n = 40000

10(b)

1. Find the actual length of the road using Map B's scale.

Map B has scale 1:650001:65000.

Actual length of road
=50×65000=3250000 cm.=50\times 65000=3250000\text{ cm}.

2. Convert the actual road length to its length on Map A using the scale from part (a).

From part (a), Map A has scale 1:400001:40000.

Length on Map A
=325000040000=81.25 cm.=\frac{3250000}{40000}=81.25\text{ cm}.

Answer

81.25 cm81.25\text{ cm}

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