Calculate $\dfrac{-(-11.8)-\sqrt{(-11)^2-7\times16\times(-40)}}{2\times16}$. Answer ... There are 800 people in an auditorium, correct to the nearest hundred. State the minimum number of people that could be in the auditorium at this time. Answer ... people

1. Simplify the signs and calculate the value of the expression

$\frac{-(-11.8)-\sqrt{(-11)^2-7\times16\times(-40)}}{2\times16}$
$=\frac{11.8-\sqrt{121+4480}}{32}$
$=\frac{11.8-\sqrt{4601}}{32}$
$=\frac{11.8-67.830\ldots}{32}$
$=-1.7509\ldots$
$\approx -1.75$

1. Find the minimum whole number that rounds to 800 to the nearest hundred

To round to $800$ to the nearest hundred, the number must be at least halfway between $700$ and $800$:

$750$

Hence, the minimum possible number of people is $750$.