Jack and Jill are going swimming at a pool that is one mile from their house. They leave home simultaneously. Jill rides her bicycle to the pool at a constant speed of 10 miles per hour. Jack walks to the pool at a constant speed of 4 miles per hour. How many minutes before Jack does Jill arrive?
A. 5
B. 6
C. 8
D. 9
E. 10

Distance = speed × time中文
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Worked solution

1. 2015 AMC 8 官方解析

吉尔用时：1÷10×60=61 \div 10 \times 60 = 6（分钟），杰克用时：1÷4×60=151 \div 4 \times 60 = 15（分钟），15−6=915 - 6 = 9（分钟），吉尔比杰克早到 9 分钟。

Answer

D. 9

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