Tank A and Tank B shown below are empty at first. Tank A has a base area of 441 cm^2. When water was poured into Tank A, some of the water flowed into Tank B through the hole which was just above Tank B. Tank B was $\tfrac{4}{7}$ filled and the total amount of water in both tanks became 5324 cm^3.

1. Determine the final height of the water in Tank A

Since water flowed into Tank B but Tank B was only $\frac{4}{7}$ filled, the water in Tank A must have stopped overflowing. This means the final water level in Tank A is exactly at the level of the hole. The hole is just above Tank B, so its height is equal to the height of Tank B, which is $4\text{ cm}$.

$\text{Height of water in Tank A} = 4\text{ cm}$

2. Calculate the volume of water in Tank A

$\text{Volume of water in Tank A} = \text{Base Area} \times \text{Height}$
$\text{Volume} = 441 \times 4 = 1764\text{ cm}^3$

1. Find the volume of water in Tank A (result from part a)

Since the hole is just above Tank B, the water level in Tank A is at the height of Tank B, which is $4\text{ cm}$.
Volume of water in Tank A $= 441 \times 4 = 1764\text{ cm}^3$

2. Find the volume of water in Tank B

Volume of water in Tank B $= 5324 - 1764 = 3560\text{ cm}^3$

3. Find the total capacity of Tank B

Tank B is $\frac{4}{7}$ filled, so $4$ units represent $3560\text{ cm}^3$.
$1$ unit $= 3560 \div 4 = 890\text{ cm}^3$
Capacity of Tank B ($7$ units) $= 890 \times 7 = 6230\text{ cm}^3$