起初，朱利安（Julian）和凯尔文（Kelvin）面对相同的方向。随后，朱利安逆时针旋转了 45∘45^\circ，而凯尔文顺时针旋转了 135∘135^\circ 后面对正北。朱利安最终面对什么方向？ 答：___

认识角及角的大小English
先不看答案，让 AI 诊断你卡在哪里？

它不会直接告诉你答案，而是问你卡在哪一步看看 AI 是怎么陪你一步步弄懂这道题的

完整解法

3

1. Determine the initial direction both were facing by working backwards from Kelvin's final direction.

Kelvin turned 135∘135^\circ clockwise to face North.
Working backwards, the initial direction is 135∘135^\circ anti-clockwise from North.
135∘=3×45∘135^\circ = 3 \times 45^\circ, which is 3 compass points anti-clockwise from North.
North →\rightarrow North-West →\rightarrow West →\rightarrow South-West.
So, both Julian and Kelvin were initially facing South-West.

2. Determine Julian's final direction.

Julian was initially facing South-West.
He turned 45∘45^\circ anti-clockwise.
45∘45^\circ anti-clockwise from South-West is South.

答案

South-West

AI 分析，可能出错

用 AI 批改，圈出写错的那一步，并自动将你的薄弱点存入错题本，形成你的错因库。

同一知识点的其他题

  1. 1如图所示，WXYZ 是一个梯形，AXYB 是一个菱形。XBC 和 XAZ 是直线。WX // ZY，BC = BY，∠XAB=82∘\angle XAB = 82^\circ，∠ZYB=19∘\angle ZYB = 19^\circ 且 ∠WZX=57∘\angle WZX = 57^\circ…
  2. 2在下图中，ABCD 是一个梯形。AF 和 EC 是直线。 佩珊写了四个陈述来描述该图形。 陈述 A：∠AED=∠ABC\angle AED = \angle ABC 陈述 B：∠EDA=∠FDC\angle EDA = \angle FDC 陈述 C：∠ABC+∠ECB=180∘\angle ABC + \angle ECB = 180^\circ…
  3. 3在下图中，ABGF 和 BCDG 是菱形。∠ABF=31∘\angle ABF = 31^\circ，∠CBG=40∘\angle CBG = 40^\circ 且 EF 平行于 DG。 求 ∠FGD\angle FGD。 求 ∠DFE\angle DFE。
  4. 4图中，PQ = PS 且 SRP 是一条直线。求 ∠RQS\angle\text{RQS}。 答：___ ∘^\circ
  5. 53.76°= 度 分 秒．