通过考虑 (2x3−x2)10\left(\dfrac{2}{x^3}-x^2\right)^{10} 展开式中的通项,说明为什么其中不含 x6x^6 项。 求 (2x3−x2)10(3−x68)\left(\dfrac{2}{x^3}-x^2\right)^{10}\left(3-\dfrac{x^6}{8}\right) 展开式中 x6x^6 的系数。

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完整解法

7(a)

1. Write down the general term of the expansion

The general term is given by:
Tr+1=(10r)(2x3)10−r(−x2)rT_{r+1} = \binom{10}{r} \left(\frac{2}{x^3}\right)^{10-r} (-x^2)^r

2. Simplify the general term to isolate the power of $x$

Tr+1=(10r)210−rx−3(10−r)(−1)rx2rT_{r+1} = \binom{10}{r} 2^{10-r} x^{-3(10-r)} (-1)^r x^{2r}
Tr+1=(10r)210−r(−1)rx−30+3r+2rT_{r+1} = \binom{10}{r} 2^{10-r} (-1)^r x^{-30+3r+2r}
Tr+1=(10r)210−r(−1)rx5r−30T_{r+1} = \binom{10}{r} 2^{10-r} (-1)^r x^{5r-30}

3. Equate the power of $x$ to 6 and solve for $r$ to explain the absence of the term

For the term in x6x^6, we require the power of xx to be 6:
5r−30=65r - 30 = 6
5r=365r = 36
r=7.2r = 7.2
Since rr must be an integer (0⩽r⩽100 \leqslant r \leqslant 10), and 7.27.2 is not an integer, there is no term in x6x^6.

答案

Since r=7.2r = 7.2 is not an integer, there is no term in x6x^6.

7(b)

1. Identify the terms from the binomial expansion needed to form $x^6$ in the product.

To find the term in x6x^6 in the expansion of (2x3−x2)10(3−x68)\left(\frac{2}{x^3}-x^2\right)^{10}\left(3-\frac{x^6}{8}\right), we consider the product of terms.
We need:
(Term in x6x^6 from expansion) ×3\times 3 ++ (Term in x0x^0 from expansion) ×(−x68)\times \left(-\frac{x^6}{8}\right).
From part (a), there is no term in x6x^6 in the expansion of (2x3−x2)10\left(\frac{2}{x^3}-x^2\right)^{10}. Thus, we only need to find the constant term (x0x^0).

2. Find the value of $r$ for the constant term in the binomial expansion.

The general term of (2x3−x2)10\left(\frac{2}{x^3}-x^2\right)^{10} is:
Tr+1=(10r)(2x3)10−r(−x2)r=(10r)210−r(−1)rx5r−30T_{r+1} = \binom{10}{r} \left(\frac{2}{x^3}\right)^{10-r} (-x^2)^r = \binom{10}{r} 2^{10-r} (-1)^r x^{5r-30}
For the constant term, the power of xx must be 00:
5r−30=0  ⟹  r=65r - 30 = 0 \implies r = 6

3. Calculate the coefficient of the constant term.

Substitute r=6r = 6 into the general term:
T7=(106)210−6(−1)6x0T_7 = \binom{10}{6} 2^{10-6} (-1)^6 x^0
T7=210×24×1=210×16=3360T_7 = 210 \times 2^4 \times 1 = 210 \times 16 = 3360
So, the constant term is 33603360.

4. Calculate the final coefficient of $x^6$ in the product.

The term in x6x^6 in the product is:
3360×(−x68)=−420x63360 \times \left(-\frac{x^6}{8}\right) = -420x^6
Therefore, the coefficient of x6x^6 is −420-420.

答案

−420-420

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