一位博主观察到他的博客平均每天有 3.2 个访客。假设其服从泊松分布,

  1. (i)

    求他的博客在两天时间内收到至少 5 个但少于 10 个访客的概率,

  2. (ii)

    使用合适的近似法,求他的博客在某一特定周内收到超过 30 个访客的概率。

  3. (iii)

    解释为什么泊松分布可能不是他的一年内博客访客人数的良好模型。

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完整解法

7(i)

1. Define the random variable and determine the mean for the given time period.

Let XX be the number of visitors over a two-day period.
Mean, λ=3.2×2=6.4\lambda = 3.2 \times 2 = 6.4
Thus, X∼Po(6.4)X \sim \text{Po}(6.4)

2. Formulate the correct probability statement and evaluate it.

The probability that the blog receives at least 5 but fewer than 10 visitors is P(5≤X<10)P(5 \le X < 10).
Since XX is a discrete random variable, this is equivalent to P(5≤X≤9)P(5 \le X \le 9).
P(5≤X≤9)=P(X≤9)−P(X≤4)P(5 \le X \le 9) = P(X \le 9) - P(X \le 4)
Using a graphing calculator:
P(5≤X≤9)≈0.88602−0.23512P(5 \le X \le 9) \approx 0.88602 - 0.23512
P(5≤X≤9)≈0.65090≈0.651 (to 3 s.f.)P(5 \le X \le 9) \approx 0.65090 \approx 0.651 \text{ (to 3 s.f.)}

答案

0.651

7(ii)

1. Find the expected number of visitors in a week to set up the appropriate Poisson distribution.

Let WW be the number of visitors in a week (7 days).
The expected number of visitors, λ=3.2×7=22.4\lambda = 3.2 \times 7 = 22.4.
So, W∼Po(22.4)W \sim \text{Po}(22.4).

2. State the suitable normal approximation and its parameters.

Since the mean λ=22.4>10\lambda = 22.4 > 10, WW can be suitably approximated by a normal distribution.
The approximate distribution is Y∼N(μ,σ2)Y \sim \text{N}(\mu, \sigma^2) where μ=22.4\mu = 22.4 and σ2=22.4\sigma^2 = 22.4.
Thus, Y∼N(22.4,22.4)Y \sim \text{N}(22.4, 22.4).

3. Apply continuity correction and evaluate the required probability.

We need to find the probability that the blog receives more than 30 visitors, which is P(W>30)P(W > 30) or equivalently P(W≥31)P(W \ge 31).
Applying continuity correction for the continuous approximation:
P(W≥31)≈P(Y>30.5)P(W \ge 31) \approx P(Y > 30.5)
Using a graphing calculator with mean 22.422.4 and standard deviation 22.4\sqrt{22.4}:
P(Y>30.5)≈0.043501P(Y > 30.5) \approx 0.043501
≈0.0435 (to 3 s.f.)\approx 0.0435 \text{ (to 3 s.f.)}

答案

0.04350.0435

7(iii)

1. Identify a violated assumption of the Poisson distribution in the context of a long time period.

For a Poisson distribution to be a valid model, the events must occur at a constant average rate. Over an entire year, the average rate of 3.2 visitors per day is highly unlikely to remain constant due to real-world factors such as varying popularity, seasonal trends, holidays, or how often the blogger posts new content.

答案

The assumption of a constant average rate of visitors is unlikely to hold over a long period such as a year, as the blog's popularity may fluctuate due to seasonal variations, trends, or the frequency of new posts.

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