Math topic中文

Telescoping and splitting fractions

Split each fraction into a difference of two terms so that intermediate terms cancel, e.g. 1/(n(n+1)) = 1/n - 1/(n+1).

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Practice questions

  1. 1等差数列{an}\{a_{n}\}的前nn项和为SnS_{n},数列{bn}\{b_{n}\}为等比数列,Sn=n2+nS_{n}\text{=}n^{2}\text{+}n,b1=a1,b2=a1a22.b_{1}\text{=}a_{1}\text{,}b_{2}\text{=}\dfrac{a_{1}a_{2}}{2}\text{.}…
  2. 2已知在数列{an}\{a_{n}\}中,a1=1a_{1}=1,其前nn项和为sns_{n},且an=2sn22sn−1(n⩾2)(1)a_{n}= \dfrac {2 s_{ n }^{ 2 }}{2s_{n}-1}(n\geqslant 2)(1)证明{1sn}\{ \dfrac {1}{s_{n}}\}…
  3. 3What is the value of the product (1+11)⋅(1+12)⋅(1+13)⋅(1+14)⋅(1+15)⋅(1+16)(1 + \frac{1}{1}) \cdot (1 + \frac{1}{2}) \cdot (1 + \frac{1}{3}) \cdot (1 + \frac{1}{4}) \cdot (1 + \frac{1}{5}) \cdot (1 + \frac{1}{6})…
  4. 4已知数列{an}\{a_{n}\}满足a1=1a_{1}=1,且an+1=2an3an+2(n∈N∗).(1)a_{n+1}=\dfrac{2{{a}_{n}}}{3{{a}_{n}}+2}(n\in N^{*}).(1)证明:数列{2an}\left\{\dfrac{2}{{{a}_{n}}}\right\}…