A study was conducted on a group of pre-diabetic seniors to examine whether the number of hours of exercise per week (tt) has any effect on their fasting blood sugar levels (SS, measured in mg/dL). The results were as follows.
tt1.51.82.12.42.53.13.54.2
SS1191081009593888685

  1. (a)

    Draw the scatter diagram for these values, labelling the axes.

  2. (b)

    Comment on whether a linear model would be appropriate, referring both to the scatter diagram and the context of the question.

  3. (c)

    By considering the shape of the following graphs, explain which model is the most appropriate for the data collected, where aa and bb are positive constants.

    A: S=a+bt2,B: S=a+bt,C: S=a+bln⁡t.\textbf{A: } S = a + bt^2, \qquad \textbf{B: } S = a + \frac{b}{t}, \qquad \textbf{C: } S = a + b \ln t.

  4. (d)

    Using the appropriate model selected above, find the value of the product moment correlation coefficient,

  5. (e)

    Using the appropriate model selected above, find the equation of the regression line of SS on tt, and hence find an estimate of the exercise time required for the fasting blood sugar to be 99 mg/dL. Comment on the reliability of your answer.

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Worked solution

8(a)

1. Draw and label the axes with appropriate scales.

Draw the horizontal axis labelled tt (hours per week) with a scale covering 00 to 4.54.5.
Draw the vertical axis labelled SS (mg/dL) with a scale covering at least 8080 to 125125.

2. Plot the given data points accurately on the scatter diagram.

Plot the 88 coordinates exactly as given in the table:
(1.5,119),(1.8,108),(2.1,100),(2.4,95),(2.5,93),(3.1,88),(3.5,86),(4.2,85)(1.5, 119), (1.8, 108), (2.1, 100), (2.4, 95), (2.5, 93), (3.1, 88), (3.5, 86), (4.2, 85)

Answer

(A scatter diagram with the horizontal axis labelled tt and vertical axis labelled SS, containing the 8 plotted points)

8(b)

1. Comment on the appropriateness using the scatter diagram.

From the scatter diagram, the plotted points do not lie close to a straight line. Instead, they follow a curve where the rate of decrease of SS slows down as tt increases.

2. Comment on the appropriateness using the context of the question.

In the context of the question, if a linear model with a negative gradient were used, the fasting blood sugar level SS would continue to decrease at a constant rate and eventually become negative for large values of exercise hours tt. Since blood sugar levels cannot be negative and must taper off to a safe, positive baseline, a linear model is not appropriate.

Answer

A linear model is not appropriate because the points on the scatter diagram follow a non-linear curve, and in context, a linear model would eventually predict impossible negative blood sugar levels for large hours of exercise.

8(c)

1. Observe the trend in the provided data.

From the data points provided in the table, as tt increases, SS decreases.

2. Evaluate the shapes of the proposed models given that $a$ and $b$ are positive.

For t>0t > 0 and b>0b > 0:

  • Model A (S=a+bt2S = a + bt^2) represents a positive quadratic curve, meaning SS increases as tt increases.
  • Model C (S=a+bln⁡tS = a + b \ln t) represents a logarithmic curve, meaning SS also increases as tt increases.
  • Model B (S=a+btS = a + \frac{b}{t}) represents a hyperbola where SS decreases as tt increases.

3. Conclude the most appropriate model based on the matching trend.

Since the scatter diagram (and data) shows a decreasing trend, Model B is the most appropriate as it is the only model that yields a decreasing graph.

Answer

Model B

8(d)

1. Identify the transformed variables from the appropriate model deduced in part (c).

From the data, SS decreases as tt increases. Since b>0b > 0, the only appropriate model from part (c) that results in a decreasing relationship is B: S=a+bt\textbf{B: } S = a + \frac{b}{t}, because 1t\frac{1}{t} decreases as tt increases.

The linear relationship is between 1t\frac{1}{t} and SS.

2. Compute the product moment correlation coefficient using a graphing calculator.

Using a graphing calculator, input the data pairs (1t,S)\left(\frac{1}{t}, S\right):
(11.5,119),(11.8,108),…,(14.2,85)\left(\frac{1}{1.5}, 119\right), \left(\frac{1}{1.8}, 108\right), \dots, \left(\frac{1}{4.2}, 85\right)

r=0.988065⋯≈0.988 (to 3 s.f.)r = 0.988065\dots \approx 0.988 \text{ (to 3 s.f.)}

Answer

0.9880.988

8(e)

1. Find the equation of the regression line based on the chosen model.

From part (c), Model B (S=a+btS = a + \frac{b}{t}) is the most appropriate as the blood sugar SS decreases at a decreasing rate for increasing positive values of tt, and a,b>0a, b > 0.
Using a graphing calculator with X=1tX = \frac{1}{t} and Y=SY = S:
a=62.438a = 62.438
b=81.661b = 81.661
The regression equation is S=62.4+81.7tS = 62.4 + \frac{81.7}{t} (to 3 s.f.).

2. Estimate the exercise time for a blood sugar level of $99$ mg/dL.

Substitute S=99S = 99 into the regression equation:
99=62.438+81.661t99 = 62.438 + \frac{81.661}{t}
36.562=81.661t36.562 = \frac{81.661}{t}
t=81.66136.562≈2.2335t = \frac{81.661}{36.562} \approx 2.2335
The estimated exercise time is 2.232.23 hours (to 3 s.f.).

3. Comment on the reliability of the estimate.

The estimate is reliable because S=99S = 99 lies well within the collected data range for fasting blood sugar levels (85≤S≤11985 \le S \le 119), which means the prediction involves interpolation.

Answer

Equation: S=62.4+81.7tS = 62.4 + \frac{81.7}{t}
Estimate: t≈2.23t \approx 2.23 hours
Reliability: The estimate is reliable as S=99S=99 falls within the data range (interpolation).

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