A, B and C are three points on horizontal ground.
The bearing of A from B is 040°.

1. Find the reverse bearing by adding $180^\circ$.

Bearing of A from B $= 040^\circ$.

So bearing of B from A
$= 040^\circ + 180^\circ = 220^\circ.$

1. Use the bearing of B from A from part (a).

From part (a), the bearing of B from A is
$220^\circ.$

2. Use the angle at A to find the bearing of C from A.

At A, the angle between $AB$ and $AC$ is $65^\circ$.

From the diagram, $AC$ is to the left of the direction $AB$ when measured as a bearing, so
$\text{bearing of C from A}=220^\circ-65^\circ=155^\circ.$