Mrs Tan planned to earn an interest of $1000 at the end of 5 years by investing her money in a bank. The rate of compound interest was fixed at 1.25% per annum. Find the amount of money she needed to deposit in the bank. Answer $ ...

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Worked solution

2

1. Form the compound amount and interest in terms of the principal

Let the amount deposited be $P.

After 5 years,
Amount=P(1+1.25100)5=P(1.0125)5.\text{Amount}=P\left(1+\frac{1.25}{100}\right)^5=P(1.0125)^5.

The interest earned is
P(1.0125)5−P.P(1.0125)^5-P.

2. Set up and solve the equation for the required deposit

Since the interest earned is $1000,
P(1.0125)5−P=1000P(1.0125)^5-P=1000
P[(1.0125)5−1]=1000P\left[(1.0125)^5-1\right]=1000
P=1000(1.0125)5−1.P=\frac{1000}{(1.0125)^5-1}.

3. Evaluate and round the money value appropriately

P=10001.0640821536−1P=\frac{1000}{1.0640821536-1}
P=15604.96…P=15604.96\ldots

So the amount she needed to deposit was
$15604.97 correct to the nearest cent.\$15604.97 \text{ correct to the nearest cent}.

Answer

$15604.97

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