Mrs Teo is a Mathematics tutor. She offers tutorial sessions for Lower Secondary and Upper Secondary students on weekdays and on weekends. Each student attends one session a week for 4 sessions in every month. The matrix N shows the number of students she tutors every month. Columns correspond to Lower Secondary (first column) and Upper Secondary (second column). Rows correspond to Weekday (first row) and Weekend (second row). N=(76 43)N = \begin{pmatrix}7 & 6 \\\ 4 & 3\end{pmatrix}

  1. (a)

    Evaluate the matrix M=4NM = 4N.

    Answer ...

  2. (b)

    Mrs Teo charges $70 for each Lower Secondary session and $80 for each Upper Secondary session.

    Represent the session charges in a 2×1 column matrix C.

    Answer C =

  3. (c)

    Evaluate the matrix P=MCP = MC.

    Answer P =

  4. (d)

    State what the elements of P represent.

    Answer ...

  5. (e)

    Mrs Teo wants to increase her tuition fees for the weekend sessions by 10% for the last 3 months before examinations start.
    The number of students registered for the weekday sessions are 10 Lower Secondary students and 8 Upper Secondary students. On weekends she has 3 Lower Secondary students and 2 Upper Secondary students.

    Calculate the total amount of money she earns during this 3 month period.

    Answer ...

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Worked solution

2(a)

1. Multiply each entry of $N$ by $4$.

M=4N=4(7643)=(4(7)4(6)4(4)4(3))=(28241612)M=4N=4\begin{pmatrix}7&6\\4&3\end{pmatrix}=\begin{pmatrix}4(7)&4(6)\\4(4)&4(3)\end{pmatrix}=\begin{pmatrix}28&24\\16&12\end{pmatrix}

Answer

M=(28241612)M=\begin{pmatrix}28&24\\16&12\end{pmatrix}

2(b)

1. Place the Lower Secondary and Upper Secondary charges into a $2\times1$ column matrix in the correct order.

Since the columns of NN are ordered as Lower Secondary, then Upper Secondary,
C=(Lower Secondary chargeUpper Secondary charge)=(7080).C=\begin{pmatrix}\text{Lower Secondary charge}\\\text{Upper Secondary charge}\end{pmatrix}=\begin{pmatrix}70\\80\end{pmatrix}.

Answer

C=(7080)C=\begin{pmatrix}70\\80\end{pmatrix}

2(c)

1. Multiply the $2\times2$ matrix $M$ by the $2\times1$ matrix $C$.

Using
M=(28241612),C=(7080),M=\begin{pmatrix}28&24\\16&12\end{pmatrix},\qquad C=\begin{pmatrix}70\\80\end{pmatrix},
P=MC=(28241612)(7080)P=MC=\begin{pmatrix}28&24\\16&12\end{pmatrix}\begin{pmatrix}70\\80\end{pmatrix}
=(28(70)+24(80)16(70)+12(80))=\begin{pmatrix}28(70)+24(80)\\16(70)+12(80)\end{pmatrix}
=(1960+19201120+960)=\begin{pmatrix}1960+1920\\1120+960\end{pmatrix}
=(38802080).=\begin{pmatrix}3880\\2080\end{pmatrix}.

Answer

P=(38802080)P=\begin{pmatrix}3880\\2080\end{pmatrix}

2(d)

1. Interpret each element of $P$ according to the row categories after multiplying the number of monthly sessions by the session charges.

Since MM gives the total number of sessions per month for each category of student, and CC gives the charge per session, P=MC=(38802080)P=MC=\begin{pmatrix}3880\\2080\end{pmatrix} gives the monthly income from the two rows: weekday sessions and weekend sessions respectively.

Answer

The elements of PP represent the total monthly tuition fees, in dollars, from weekday sessions and weekend sessions respectively.

2(e)

1. Find the weekend session charges after a 10% increase.

Weekend Lower Secondary charge:
70×1.10=7770\times 1.10=77
Weekend Upper Secondary charge:
80×1.10=8880\times 1.10=88

2. Calculate the total earnings for one session in a week from all registered students.

Weekday earnings per weekly session:
10(70)+8(80)=700+640=134010(70)+8(80)=700+640=1340
Weekend earnings per weekly session:
3(77)+2(88)=231+176=4073(77)+2(88)=231+176=407
Total earnings per week:
1340+407=17471340+407=1747

3. Convert the weekly earnings to total earnings over 3 months.

Each student attends 44 sessions every month.

For 33 months, number of weekly sessions per student is
4×3=124\times 3=12
Total amount earned:
1747×12=209641747\times 12=20964

Answer

$19 776

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