The times taken, in minutes, by 14 students to complete a Mathematics assignment are recorded. The results are shown in the stem-and-leaf diagram.

  1. (a)

    Find the modal time.

    Answer ... mins

  2. (b)

    Find the percentage of students who took at most 20 minutes to complete the assignment.

    Answer ... %

  3. (c)

    The time taken for the 15th student to complete the assignment is recorded.
    The range increases to 31 minutes.
    Find two possible times this student spent completing the assignment.

    Answer ... mins or ... mins

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Worked solution

19(a)

1. Find the value with the highest frequency

From the stem-and-leaf diagram, the times include
23,23,2323, 23, 23.

No other time appears more than twice, so the modal time is 2323 minutes.

Answer

2323 mins

19(b)

1. Identify students who took at most 20 minutes and calculate the percentage

Times at most 2020 minutes are 11,15,19,2011, 15, 19, 20, so there are 44 students.

Total number of students =14=14.

414×100%=28.571…%=28.6%\frac{4}{14}\times 100\%=28.571\ldots\%=28.6\%

Answer

314×100%=21.4%\dfrac{3}{14}\times 100\%=21.4\%

19(c)

1. Find the original smallest and greatest times

From the stem-and-leaf diagram, the smallest time is 1111 minutes and the greatest time is 4040 minutes.

Original range =40−11=29=40-11=29 minutes.

2. Find the possible new times that make the new range 31 minutes

The new range is 3131 minutes.

If the new time is the new smallest value, then
40−x=3140-x=31
x=9.x=9.

If the new time is the new greatest value, then
x−11=31x-11=31
x=42.x=42.

Answer

99 mins or 4242 mins

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