Roy made a model of his yacht with a scale of 1: 40.

  1. (a)

    The actual length of the yacht is 12.5 m, find the length of the model in cm.

    Answer ...cm

  2. (b)

    Roy wants to spray paint his yacht. He can select either of the following options to paint his yacht.

    Option A: A lump sum payment of $1 000
    Option B: Payment for cost of paint at $5.50 per m2
    [Cost of manpower is included in both options]

    If the total surface area of the model to be painted is 937.5 cm2, find the surface area of his yacht. Which one of the two options should Roy select to paint his yacht?
    [Show your workings clearly]

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Worked solution

10(a)

1. Convert the actual yacht length from metres to centimetres and apply the scale factor.

12.5 m=12.5×100=1250 cm12.5\text{ m}=12.5\times100=1250\text{ cm}

Scale 1:401:40 means

model length=125040=31.25 cm.\text{model length}=\frac{1250}{40}=31.25\text{ cm}.

Answer

31.25 cm31.25\text{ cm}

10(b)

1. Use the area scale factor to find the actual surface area in $\text{cm}^2$.

Scale of model : actual =1:40=1:40.

For area,
model area:actual area=12:402=1:1600.\text{model area} : \text{actual area}=1^2:40^2=1:1600.

Actual surface area
=937.5×1600=1 500 000 cm2.=937.5\times1600=1\,500\,000\text{ cm}^2.

2. Convert the actual surface area from $\text{cm}^2$ to $\text{m}^2$.

Since 1 m2=10 000 cm21\text{ m}^2=10\,000\text{ cm}^2,
1 500 000 cm2=1 500 00010 000=150 m2.1\,500\,000\text{ cm}^2=\frac{1\,500\,000}{10\,000}=150\text{ m}^2.

3. Calculate the cost under Option B and compare it with Option A.

Option B cost
=150×$5.50=$825.=150\times \$5.50=\$825.

Option A cost =$1000=\char36{}1000.

Since $825<$1000\char36{}825<\char36{}1000, Option B is cheaper.

Answer

Surface area of yacht =150 m2=150\text{ m}^2. Roy should select Option B.

AI analysis — may contain mistakes.

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