The figure below is formed by five straight lines, AC, AD, BD, BE and CE. Find the sum of ∠p\angle p, ∠q\angle q, ∠r\angle r and ∠s\angle s. Ans : ___ ∘^\circ

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1. Identify the exterior angle of the triangle containing angles p and q

Let the intersection of ADAD and BEBE be FF. In △BDF\triangle BDF, the exterior angle at FF is ∠AFE=∠p+∠q\angle AFE = \angle p + \angle q.

2. Identify the exterior angle of the triangle containing angles r and s

Let the intersection of ACAC and CECE be GG. In △CEG\triangle CEG, the exterior angle at GG is ∠AGC=∠r+∠s\angle AGC = \angle r + \angle s.

3. Use the sum of angles in a quadrilateral to find the sum of p, q, r, and s

Consider the quadrilateral formed by the intersections of AC,AD,BE,CEAC, AD, BE, CE. Let the intersection of ACAC and BEBE be HH, and the intersection of ADAD and CECE be II. The interior angles of quadrilateral FGHIFGHI are ∠F=∠p+∠q\angle F = \angle p + \angle q, ∠G=∠r+∠s\angle G = \angle r + \angle s, ∠H=60∘\angle H = 60^\circ (vertically opposite), and ∠I=140∘\angle I = 140^\circ (vertically opposite). The sum of interior angles of a quadrilateral is 360∘360^\circ.
(∠p+∠q)+(∠r+∠s)+60∘+140∘=360∘(\angle p + \angle q) + (\angle r + \angle s) + 60^\circ + 140^\circ = 360^\circ
∠p+∠q+∠r+∠s=360∘−200∘=160∘\angle p + \angle q + \angle r + \angle s = 360^\circ - 200^\circ = 160^\circ

Answer

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