A model consists of a solid hemisphere attached to a solid cylinder as shown in diagram. The height of the cylinder is 26 cm and the base area is 198 cm^2.

- (a)
Calculate, giving your answers to the nearest whole number, the volume of
- (i)
the cylinder.
Answer ...
- (ii)
the hemisphere.
Answer ...
- (i)
- (b)
Part of the cylinder in the shape of a right circular cone is removed as shown in the diagram 2.

- (i)
Given that the volume of the cone removed from the model is 630 cm^3, calculate the height of the cone.
Answer ... cm
- (ii)
Calculate the total surface area of the model as shown in diagram 2, giving the answer to the nearest whole number.
Answer ... cm^2
- (i)
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Worked solution
8(a)(i)
1. Calculate the volume of the cylinder using its base area and height.
8(a)(ii)
1. Find the radius of the hemisphere using the base area of the cylinder.
Since the hemisphere has the same radius as the cylinder base,
2. Use the formula for the volume of a hemisphere.
Volume of hemisphere
3. Calculate and round the volume to the nearest whole number.
To the nearest whole number,
8(b)(i)
1. Substitute the cone volume and base area into the cone volume formula, then solve for the height.
For a cone,
Given and base area ,
So the height of the cone is to 3 significant figures.
8(b)(ii)
1. Find the common radius of the cylinder, hemisphere and cone.
Since the base area of the cylinder is ,
2. Find the slant height of the cone removed.
From part (b)(i), the height of the cone is
Using Pythagoras' theorem,
3. Write the total surface area as the sum of all exposed surfaces.
Exposed surfaces are:
- curved surface area of cylinder:
- curved surface area of hemisphere:
- circular base of cylinder:
- curved surface area of conical hole:
So
4. Calculate the total surface area and round to the nearest whole number.
To the nearest whole number,
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