In a scale drawing, Town W, X and Y are shown below. Town Z is 10 cm from Town W and 8 cm from Town Y.

- (a)
- (i)
On the diagram, construct the quadrilateral WXYZ.
- (ii)
Measure angle WZY.
Answer: ...
- (i)
- (b)
On the diagram, using compass, construct
- (i)
the perpendicular bisector of XY.
- (ii)
the angle bisector of angle WXY.
- (i)
- (c)
Mark claimed that it is possible to locate Town G which is equidistant from Points W, X and Y, and angle WXG = angle YXG. Explain whether Mark's claim is valid. Show your workings clearly.
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Worked solution
19(a)(i)
1. Locate the possible position of Z using the given distance from W.
Set the compass to . With centre , draw an arc/circle representing all points from .
2. Use the distance from Y to fix Z and complete the quadrilateral.
Set the compass to . With centre , draw an arc/circle to intersect the first arc/circle at . Mark the required intersection as , then join to and to to complete quadrilateral .
Quadrilateral constructed, with and .
19(b)(i)
1. Draw equal-radius arcs from $X$ and $Y$ to locate two points equidistant from $X$ and $Y$.
Set the compass radius to more than half of . With centre , draw arcs above and below . Using the same radius and centre , draw arcs to intersect the first pair of arcs at two points.
2. Join the two arc-intersection points to form the perpendicular bisector of $XY$.
Draw a straight line through the two arc-intersection points. This line is the perpendicular bisector of , meeting at its midpoint and at right angles.
Perpendicular bisector of constructed on the diagram.
19(b)(ii)
1. Construct equal-distance points on the two arms of the angle and use them to locate the bisector.
With centre , draw an arc cutting and at two points. Using these two points as centres and the same radius, draw arcs intersecting inside . Join to this intersection point. This line is the angle bisector of .
Angle bisector of constructed on the diagram.
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