In a scale drawing, Town W, X and Y are shown below. Town Z is 10 cm from Town W and 8 cm from Town Y.

  1. (a)
    1. (i)

      On the diagram, construct the quadrilateral WXYZ.

    2. (ii)

      Measure angle WZY.

      Answer: ...

  2. (b)

    On the diagram, using compass, construct

    1. (i)

      the perpendicular bisector of XY.

    2. (ii)

      the angle bisector of angle WXY.

  3. (c)

    Mark claimed that it is possible to locate Town G which is equidistant from Points W, X and Y, and angle WXG = angle YXG. Explain whether Mark's claim is valid. Show your workings clearly.

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Worked solution

19(a)(i)

1. Locate the possible position of Z using the given distance from W.

Set the compass to 10 cm10\text{ cm}. With centre WW, draw an arc/circle representing all points 10 cm10\text{ cm} from WW.

2. Use the distance from Y to fix Z and complete the quadrilateral.

Set the compass to 8 cm8\text{ cm}. With centre YY, draw an arc/circle to intersect the first arc/circle at ZZ. Mark the required intersection as ZZ, then join ZZ to WW and ZZ to YY to complete quadrilateral WXYZWXYZ.

Answer

Quadrilateral WXYZWXYZ constructed, with WZ=10 cmWZ=10\text{ cm} and YZ=8 cmYZ=8\text{ cm}.

19(b)(i)

1. Draw equal-radius arcs from $X$ and $Y$ to locate two points equidistant from $X$ and $Y$.

Set the compass radius to more than half of XYXY. With centre XX, draw arcs above and below XYXY. Using the same radius and centre YY, draw arcs to intersect the first pair of arcs at two points.

2. Join the two arc-intersection points to form the perpendicular bisector of $XY$.

Draw a straight line through the two arc-intersection points. This line is the perpendicular bisector of XYXY, meeting XYXY at its midpoint and at right angles.

Answer

Perpendicular bisector of XYXY constructed on the diagram.

19(b)(ii)

1. Construct equal-distance points on the two arms of the angle and use them to locate the bisector.

With centre XX, draw an arc cutting XWXW and XYXY at two points. Using these two points as centres and the same radius, draw arcs intersecting inside ∠WXY\angle WXY. Join XX to this intersection point. This line is the angle bisector of ∠WXY\angle WXY.

Answer

Angle bisector of ∠WXY\angle WXY constructed on the diagram.

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