In Sunny Island Republic, all male citizens are required to undergo a National Physical Fitness Assessment (NPFA) Test before enlisting for National Service in the army. Based on historical data, 75% of males who attempt the NPFA Test will pass the test and they are awarded either a Bronze, Silver or Gold standard. The performance at the NPFA Test is known to influence the chances of these National Servicemen being promoted to the rank of an Officer. For male citizens who fail the NPFA Test, they are required to undergo a Physical Assessment Test (PAT) at the end of their basic training. It is known that those who pass the PAT will have a chance to be promoted to the rank of an Officer. The information is summarized in the tree diagram below.

  1. (i)

    It is known that the probability that a randomly chosen serviceman is an Officer is 0.60. Find the value of aa.

  2. (ii)

    Find the probability that a randomly chosen serviceman failed his NPFA Test given that he is an Officer.

  3. (iii)

    Hence find the probability that a randomly chosen Officer passed his NPFA Test.

  4. (iv)

    Find the probability that a randomly chosen serviceman who is a Non-officer had failed his NPFA Test.

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Worked solution

7(i)

1. Set up an equation for the total probability of a randomly chosen serviceman being an Officer by summing the probabilities of all paths leading to 'Officer'.

P(Officer)=0.75(0.20×0.91+0.63×0.72+0.17×0.54)+0.25(a×0.36)\text{P}(\text{Officer}) = 0.75(0.20 \times 0.91 + 0.63 \times 0.72 + 0.17 \times 0.54) + 0.25(a \times 0.36)
0.60=0.75(0.182+0.4536+0.0918)+0.09a0.60 = 0.75(0.182 + 0.4536 + 0.0918) + 0.09a
0.60=0.54555+0.09a0.60 = 0.54555 + 0.09a

2. Solve the linear equation for $a$.

0.09a=0.60−0.545550.09a = 0.60 - 0.54555
0.09a=0.054450.09a = 0.05445
a=0.054450.09=0.605a = \frac{0.05445}{0.09} = 0.605

Answer

a=0.605a = 0.605

7(ii)

1. Calculate the probability that a serviceman fails the NPFA and becomes an Officer, using the value of $a$ found in part (i) ($a = 0.605$).

P(Fail NPFA∩Officer)=0.25×a×0.36P(\text{Fail NPFA} \cap \text{Officer}) = 0.25 \times a \times 0.36
P(Fail NPFA∩Officer)=0.25×0.605×0.36=0.05445P(\text{Fail NPFA} \cap \text{Officer}) = 0.25 \times 0.605 \times 0.36 = 0.05445

2. Apply the conditional probability formula.

P(Fail NPFA∣Officer)=P(Fail NPFA∩Officer)P(Officer)P(\text{Fail NPFA} \mid \text{Officer}) = \frac{P(\text{Fail NPFA} \cap \text{Officer})}{P(\text{Officer})}
=0.054450.60= \frac{0.05445}{0.60}
=0.09075= 0.09075

Answer

0.090750.09075

7(iii)

1. Calculate the result for part (ii) as a prerequisite (probability that an Officer failed the NPFA Test).

First, find the probability that a serviceman passed the NPFA Test and became an Officer:
P(Pass NPFA∩Officer)=0.75×[0.20(0.91)+0.63(0.72)+0.17(0.54)]=0.54555P(\text{Pass NPFA} \cap \text{Officer}) = 0.75 \times [0.20(0.91) + 0.63(0.72) + 0.17(0.54)] = 0.54555
Since P(Officer)=0.60P(\text{Officer}) = 0.60 (given in part i), the probability for part (ii) is:
P(Fail NPFA∣Officer)=0.60−0.545550.60=0.09075P(\text{Fail NPFA} \mid \text{Officer}) = \frac{0.60 - 0.54555}{0.60} = 0.09075

2. Use the complement rule to answer part (iii).

Since an Officer must have either passed or failed the NPFA Test, we subtract the result of part (ii) from 1:
P(Pass NPFA∣Officer)=1−P(Fail NPFA∣Officer)P(\text{Pass NPFA} \mid \text{Officer}) = 1 - P(\text{Fail NPFA} \mid \text{Officer})
=1−0.09075=0.90925= 1 - 0.09075 = 0.90925

Answer

0.9090.909 (to 3 s.f.) or 0.909250.90925

7(iv)

1. Calculate the unknown probability $a$ from the tree diagram (as implicitly required from part (i)).

Given P(Officer)=0.60P(\text{Officer}) = 0.60.
P(Officer)=P(Pass NPFA∩Officer)+P(Fail NPFA∩Officer)P(\text{Officer}) = P(\text{Pass NPFA} \cap \text{Officer}) + P(\text{Fail NPFA} \cap \text{Officer})
=0.75(0.20×0.91+0.63×0.72+0.17×0.54)+0.25(a×0.36)= 0.75(0.20 \times 0.91 + 0.63 \times 0.72 + 0.17 \times 0.54) + 0.25(a \times 0.36)
=0.75(0.182+0.4536+0.0918)+0.09a= 0.75(0.182 + 0.4536 + 0.0918) + 0.09a
=0.54555+0.09a= 0.54555 + 0.09a
0.54555+0.09a=0.60  ⟹  0.09a=0.05445  ⟹  a=0.6050.54555 + 0.09a = 0.60 \implies 0.09a = 0.05445 \implies a = 0.605

2. Find the total probability that a randomly chosen serviceman is a Non-officer.

P(Non-officer)=1−P(Officer)P(\text{Non-officer}) = 1 - P(\text{Officer})
=1−0.60=0.40= 1 - 0.60 = 0.40

3. Calculate the probability that a serviceman failed the NPFA test AND is a Non-officer.

P(Fail NPFA∩Non-officer)=P(Fail NPFA)×P(Non-officer∣Fail NPFA)P(\text{Fail NPFA} \cap \text{Non-officer}) = P(\text{Fail NPFA}) \times P(\text{Non-officer} \mid \text{Fail NPFA})
=0.25×[a×0.64+(1−a)×1.0]= 0.25 \times [a \times 0.64 + (1 - a) \times 1.0]
=0.25×[0.605×0.64+(1−0.605)×1.0]= 0.25 \times [0.605 \times 0.64 + (1 - 0.605) \times 1.0]
=0.25×[0.3872+0.395]= 0.25 \times [0.3872 + 0.395]
=0.25×0.7822=0.19555= 0.25 \times 0.7822 = 0.19555

4. Calculate the conditional probability that a Non-officer had failed his NPFA test.

P(Fail NPFA∣Non-officer)=P(Fail NPFA∩Non-officer)P(Non-officer)P(\text{Fail NPFA} \mid \text{Non-officer}) = \frac{P(\text{Fail NPFA} \cap \text{Non-officer})}{P(\text{Non-officer})}
=0.195550.40= \frac{0.19555}{0.40}
=0.488875≈0.489 (to 3 s.f.)= 0.488875 \approx 0.489 \text{ (to 3 s.f.)}

Answer

0.489

AI analysis — may contain mistakes.

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