Bernice invests $700 at a rate of r % per year compound interest, compounded every 3 months. At the end of 5 years the value of her investment is $854.13, correct to 2 decimal places. Calculate the value of r, correct to 3 significant figures. Answer r = ___

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Worked solution

10

1. Identify the number of compounding periods and set up the compound interest equation.

Compounded every 3 months means 44 times per year.

In 55 years, number of periods =5×4=20=5\times 4=20.

The rate per period is r4%=r400\dfrac{r}{4}\% = \dfrac{r}{400} as a multiplier increase.

700(1+r400)20=854.13700\left(1+\frac{r}{400}\right)^{20}=854.13

2. Isolate the quarterly growth factor.

(1+r400)20=854.13700\left(1+\frac{r}{400}\right)^{20}=\frac{854.13}{700}

1+r400=(854.13700)1201+\frac{r}{400}=\left(\frac{854.13}{700}\right)^{\frac{1}{20}}

3. Solve for $r$ and round to 3 significant figures.

r400=(854.13700)120−1\frac{r}{400}=\left(\frac{854.13}{700}\right)^{\frac{1}{20}}-1

r=400[(854.13700)120−1]r=400\left[\left(\frac{854.13}{700}\right)^{\frac{1}{20}}-1\right]

r=3.99998…r=3.99998\ldots

Correct to 3 significant figures,

r=4.00r=4.00

Answer

r=4.00r = 4.00

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