Chloe and Zoe are both students in Ms. Demeanor's math class. Last night they each solved half of the problems in their homework assignment alone and then solved the other half together. Chloe had correct answers to only 80% of the problems she solved alone, but overall 88% of her answers were correct. Zoe had correct answers to 90% of the problems she solved alone. What was Zoe's overall percentage of correct answers?

A. 89

B. 92

C. 93

D. 96

E. 98

1. 2017 AMC 8 官方解析

翻译：克洛伊和佐伊都是戴米娜女士的数学课的学生．昨天晚上，每个人都独自完成了一半的作业，剩下的是两个人共同完成的．克洛伊独自完成的作业正确率是 80%，总正确率是88%．佐伊独自完成的作业正确率是90%，那么佐伊全部作业的正确率是（　　）．
由于两人共同完成剩余一半的作业，所以剩下一半作业正确率相同，可以把此题看成浓度问题，独自完成题目与剩余一半并且是共同完成题目混合．
克洛伊：独自：$\frac{1}{2}$，共同：$\frac{1}{2}$， $\begin{array}{r} 80\% \\ {} \\ x\% \end{array} \begin{array}{l} \searrow \\ \ \ \ \ 88\% \\ \nearrow \end{array} \begin{array}{l} x\% - 88\% \\ {} \\ 88\% - 80\% \end{array}$， $\frac{x - 88}{88 - 80} = \frac{\frac{1}{2}}{\frac{1}{2}} = 1$，$x = 96$；
佐伊：独自：$\frac{1}{2}$，共同：$\frac{1}{2}$， $\begin{array}{r} 90\% \\ {} \\ 96\% \end{array} \begin{array}{l} \searrow \\ \ \ \ \ y\% \\ \nearrow \end{array} \begin{array}{l} 96\% - y\% \\ {} \\ y\% - 90\% \end{array}$， $\frac{96 - y}{y - 90} = 1$，$y = 93$．